if 1 is a root of the equation a y square + ay + 3 is equal to zero and y square + y + b is equal to zero then find the value of AB
Answers
Answered by
1
Step-by-step explanation:
Open in answr app
ay
2
+ay+3=0
as 1 is root then
⇒a(1)
2
+a(1)+3=0
⇒a+a=−3
⇒2a=−3
⇒a=−
2
3
y
2
+y+b=0
⇒(1)
2
+1+b=0
⇒2+b=0
⇒b=−2
∴ab=−
2
3
×−2=3
Answer verified by Toppr
Answered by
2
Answer:
Plz mark as brainliest
Step-by-step explanation:
ay2+ay+3= 0
as 1 is root then
⇒a(1)2+a(1)+3=0
⇒a+a=−3
⇒2a=−3
⇒a=−23
y2+y+b=0
⇒(1)2+1+b=0
⇒2+b=0
⇒b=−2
∴ab=−23×−2=3
Similar questions