Question

If 1 is a root of the equation ay2+ay+3=0 and y2+y+b=0, then fing ab.

Answer 1

If 1 is the root of the given equations then it would satisfy the conditions ;

a(1)^2+a(1)+3 = 0
2a = -3
a = -3/2

(1)^2+(1)+b =0
2 + b = 0
b = -2

ab = (-3/2)×-2
= 3

Answer 2

Answer:

ab= 3

Step-by-step explanation:

a(1)^2 + a(1) + 3 = 0

a + a + 3 = 0

2a + 3 = 0

2a = -3

a = -3/2

(1)^2 + (1) + b = 0

1 + 1 + b = 0

2 + b = 0

b = -2

Thus, ab= -3/2*2 = 3

( 2 gets cancelled. )