Question

If 1 is a root of the equation x2+Kx - 4 = 0, then the value of k

Answer 1

Answer:

${x}^{2} + kx - 4 = 0 \\ as \: we \: know \: {ax}^{2} + bx + c = 0 \\ a = 1 \\ b = k \\ c = ( - 4) \\ {b}^{2} - 4ac = 0 \\ = > {k}^{2} - 4.1. (- 4) = 0 \\ = > {k}^{2} + 16 = 0 \\ = > {k}^{2} = - 16 \\ = > k = \sqrt{16} \\ = > k = - 4$

so, k= -4.

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