If 1 is a root of the equations ay²+ay + 3 = 0 and y²+y+b=0, then ab equals
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if 1 is the root of this eq then it satisfy both of the eq
a(1)+a (1)+3=0
a=-3/2
1+1+b=0
b=-2
ab=-3/2×(-2)=3
ab=3
a(1)+a (1)+3=0
a=-3/2
1+1+b=0
b=-2
ab=-3/2×(-2)=3
ab=3
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