If 1 is a root of the quadratic equation 2x2 +Px+ 4 = 0, then find the other root and also find the value of P
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Answered by
1
1(.α)=2
α.=2
α+1=-p/2
p=-6
α.=2
α+1=-p/2
p=-6
Answered by
4
2x²+Px+4 = 0
1 is a root of the given equation.
Let the other root be "a"
We know that,
Product of roots = constant/x² coefficient
1×a = 4/2
a = 2
Therefore,the other root of the equation is 2
Now, to find P....
We know that,
Sum of roots = -(x coefficient)/x² coefficient
(1+2) = -P/2
3 = -P/2
-P = 6
P = -6
Hope it helps.....
1 is a root of the given equation.
Let the other root be "a"
We know that,
Product of roots = constant/x² coefficient
1×a = 4/2
a = 2
Therefore,the other root of the equation is 2
Now, to find P....
We know that,
Sum of roots = -(x coefficient)/x² coefficient
(1+2) = -P/2
3 = -P/2
-P = 6
P = -6
Hope it helps.....
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