Question

.If 1 is a root of the quadratic equation ax²+ax+3=0 and x²+x+b=0 then the value of ab is

Answer 1

Answer:

idk

Step-by-step explanation:

Answer 2

AnsWer :

3.

GiveN :

• One roots of Quadratic Equation is q = 1.

SolutioN :

★ Putting the Value ( 1 )

$\tt : \implies a {x}^{2} + ax + 3 = 0.$

$\tt : \implies a {\Big(1\Big)}^{2} + a + 3 = 0.$

$\tt : \implies a + a+ 3 = 0.$

$\tt : \implies 2a+ 3 = 0.$

$\tt : \implies 2a = - 3.$

$\tt : \implies a = \dfrac{ - 3}{2} .$

Now,

$\tt : \implies {x}^{2} + x + b = 0.$

$\tt : \implies {\Big(1\Big)}^{2} + 1 + b = 0.$

$\tt : \implies b = - 2.$

A/Q,

→ ab =( - 3 /2 ) * ( - 2 )= 6/2 = 3.

Therefore the value of ab is 3.