Question

if 1 is a zero of a polynomial p(x)=ax^2-3(9-1)x-1 then find the value of a​

Answer 1

Answer:

the answer will be 24

Step-by-step explanation:

$p(x) = ax {}^{2} - 3(9 - 1)x - 1 \\ = p(1) = a1 {}^{2} - 3(9 - 1)1 - 1 = 0 \\ = a - 3(9 - 1) = 0 \\ = a - 3 \times 8 = 0 \\ = a - 24 = 0 \\ a = 24$

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