If 1 is a zero of a polynomial P(x)=ax^2 - 3(a -1) -1 then find the value of a
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the above pic is wrong
p(1)=a×1×2-3(a_1)
=2a_3a+3=0
_a=_3
a=3
p(1)=a×1×2-3(a_1)
=2a_3a+3=0
_a=_3
a=3
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