Math, asked by Verma155, 11 months ago

 If '1' is a zero of p(x) = ax^2 - 3 (a-1) x -1 , then the value of 'a' is
a. 1
b. 0
c. -1
d. 2​

Answers

Answered by TakenName
0

A specific value that makes p(x) equal to 0 is called 'zero'.

Since 1 is the zero, we know that p(1) equals 0.

By substitution of x=1,

p(1) = a - 3(a-1) - 1

0 = a - 3a + 3 - 1

0 = -2a + 2

∴a = 1

The correct answer is choice a.

Answered by Anonymous
0

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