Question

If '1'is a zero of p(x)= ax^2 - 3(a-1) x-1 then the value of 'a'is ​

Answer 1

Answer:

=> 1

Step-by-step explanation:

p(x) = ax²- 3(a-1)x -1

Given, 1 is its zero

p(x) = a(1)² -3(a-1)1 -1 = 0

a - 3a+3 -1 = 0

-2a + 2 = 0

-2a = -2

a = -2/-2

a = 1

Answer 2

Step-by-step explanation:

Answer: 1

Step-by-step explanation:

p(x) = ax²- 3(a-1)x -1

Given, 1 is its zero

p(x) = a(1)² -3(a-1)1 -1 = 0

a - 3a+3 -1 = 0

-2a + 2 = 0

-2a = -2

a = -2/-2

a = 1