Question

If 1 is a zero of polynomial p(x)=ax^2-3(a-1)-1, then find the calue of



a.

Answer 1

p(x) = ax²- 3(a - 1) - 1

1 is the zero of the polynomial. This means that wherever p(1) = 0. So wherever there is x, substitute 1.

p(1) = 0

0 = a - 3a + 3 - 1

0 = -2a + 2

2a = 2

a = 1

Hope this helps! :)