Question

If 1 is a zero of polynomial p(x) = ax? - 3(2-1) - 1, then the value of a is (a) 2 (6)3 (c) 1 (d)-2​

Answer 1

Answer:

Option (c) 1

Step-by-step explanation:

Given: p(x)=ax2−3(a−1)x−1

One of the zero =1

As one of the zeroes is 1, substituting it in the polynomial 

⇒p(1)=0=a−3(a−1)−1

⇒0=−2a+3−1 

⇒a=1

I hope it will help you