Question

if - 1 is a zero of polynomial p(x)=ax cube-x square+x+4 then find a​

Answer 1

Answer:

Given,

X=-1

now put the value of X in the equation

ax³-x²+x+4=0

a(-1)³-(-1)²+(-1)+4=0

a(1)-1-1+4=0

a+2=0

a=-2

Answer 2

Step-by-step explanation:

$a {x}^{3} - {x}^{2} + x + 4 = 0 \\ if \: x = - 1 \: then \: \\ a ({ - 1})^{3} - (- {1})^{2} + ( - 1) + 4 = 0 \\ - a - 1 - 1 + 4 = 0 \\ - a - 2 + 4 = 0 \\ - a + 2 = 0 \\ a = 2$

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