Question

if 1 is a zero of polynomial p(x) = ax sq -3(a-1)-1 then find the value of a​

Answer 1

Answer:

p(x)=ax^2-3(a-1)-1

p(1)=a-3(a-1)-1=0

a-3a+3-1=0

-2a+2=0

-a+1=0

-a=-1

a=1

Answer 2

Answer:

when u put x= 1 in the polynomial then we get the value of a= 1