Question

If 1 is a zero of polynomial p(x)=ax square - 3(a-1) x-1 then find value of a

Answer 1

p(1)=0

So, ax^2-3(a-1)x-1 at x=1 will be 0

put the value of x =1

a(1)^2-3(a-1)(1)-1 =0

a-3a-3-1=0

-2a-4=0

-2a=4

a=-2