Question

if 1 is a zero of polynomial p(x)=ax²-3(a-1)x-1, theb find the value of A​

Answer 1

Step-by-step explanation:

p(1) = a×(1)^2 - 3a + 3 =0

p(1) = a -3a +3 =0

p(1) = -2a +3 = 0

p(1) = -2a = -3

p(1) = a = 3/2.

hence ,, .

value of a is 3/2.

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Answer 2

Step-by-step explanation:

a(1)^2-3(a-1)(1)-1=0

a(1)-3a+3-1=0

a-3a+2=0

-2a+2=0

-2a=-2

a=-2/-2

a=1