Math, asked by bodakuntalacchanna, 9 months ago

If 1 is a zero of polynomial p (x) = ax²- 3 (a - 1)x - 1 then find the value of a

Answers

Answered by sowmyasony
4

Answer:

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Step-by-step explanation:

p(x) = ax²- 3(a-1)x -1

Given, 1 is its zero

p(x) = a(1)² -3(a-1)1 -1 = 0

a - 3a+3 -1 = 0

-2a + 2 = 0

-2a = -2

a = -2/-2

a = 1

Answered by Sudhir1188
2

Step-by-step explanation:

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