Math, asked by JJMP, 4 months ago

if 1 is a zero of the given polynomial then find the value of a, p(x)=ax²-3(a-1)x-1​

Answers

Answered by piupaul7908gmailcom
1

Answer:

Given: p(x)=ax

2

−3(a−1)x−1

One of the zero =1

As one of the zeroes is 1, substituting it in the polynomial

⇒p(1)=0=a−3(a−1)−1

⇒0=−2a+3−1

⇒a=1

answer is 1

Answered by StudyMore2003
0

Answer:

please answer my question of maths also

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