Question

if -1 is a zero of the polymomial p (x)=ax^3-x^2+x+4, then find the value of 'a'​

Answer 1

Answer:

3

Step-by-step explanation:

-1=a(-1)³-(-1)²+(-1)+4

=> -1= -1a-1-1+4

=> -1= -1a-2+4

=> -1= -1a+2

=> -1a= -1-2

=> -1a=-3

=> a= 3

So the value of a is 3

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