If - 1 is a zero of the polynomial 2x²-x²-5x-2, find its other zeroes
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It's 2x³ .
since -1 is the zero
:. x = -1
.: x+1 = 0
so the g(x) = x+1
For zeros = p(x)/ g(x)
= 2x³-x²-5x-2 / x+1
= 2x²-3x-2
Therefore-----
2x²-3x-2 = 2x² - 4x + x - 2
= 2x ( x - 2 ) 1 ( x - 2 )
= ( 2x + 1 ) ( x - 2 )
Therefore .......
2x + 1 = 0. or. x - 2 = 0
x = -1 / 2. or x = 2
So the other zeros are -1/2 and 2 .
HOPE IT IS MOST HELPFUL!!!!!!!!!!!!!!!!
since -1 is the zero
:. x = -1
.: x+1 = 0
so the g(x) = x+1
For zeros = p(x)/ g(x)
= 2x³-x²-5x-2 / x+1
= 2x²-3x-2
Therefore-----
2x²-3x-2 = 2x² - 4x + x - 2
= 2x ( x - 2 ) 1 ( x - 2 )
= ( 2x + 1 ) ( x - 2 )
Therefore .......
2x + 1 = 0. or. x - 2 = 0
x = -1 / 2. or x = 2
So the other zeros are -1/2 and 2 .
HOPE IT IS MOST HELPFUL!!!!!!!!!!!!!!!!
AnjaliRaut:
my answer was not presentable
no problem u can edit it
I have a doubt u thanked me twice but how did u do so as only one time is allowable to me.
It can be done if u tap continuously
but it comes for me as "u've already thanked this answer"
And i will not edit my answer as it will always remind me tht i have wasted someone's points and valuable time in reading my waste answer
fine don't feel bad for ur presentation and bye,,...........
No it can be thanked twice sometimes
Once i had sent 10 thanks
Oh !!!!
Answered by
8
Ur question is wrong sis (2x²-x²-5x-2) it should be 2x³-x²-5x-2
As -1 being a zero, then x = -1
x + 1 = 0
So, x + 1 is a factor of 2x³ - x² - 5x - 2
By Division Algorithm,
Divide 2x³ - x² - 5x - 2 by x + 1 by long division
2x³ - x² - 5x - 2 ÷ x + 1 ⇒ 2x² - 3x - 2 (which u will get as quotient)
Simplifying 2x² - 3x - 2
= 2x² - 3x - 2
= 2x² - 4x + x - 2
= 2x(x-2) + 1(x-2)
= (2x+1)(x-2)
Then, x = -1/2 , 2
Hence other zeroes are -1/2 and 2
As -1 being a zero, then x = -1
x + 1 = 0
So, x + 1 is a factor of 2x³ - x² - 5x - 2
By Division Algorithm,
Divide 2x³ - x² - 5x - 2 by x + 1 by long division
2x³ - x² - 5x - 2 ÷ x + 1 ⇒ 2x² - 3x - 2 (which u will get as quotient)
Simplifying 2x² - 3x - 2
= 2x² - 3x - 2
= 2x² - 4x + x - 2
= 2x(x-2) + 1(x-2)
= (2x+1)(x-2)
Then, x = -1/2 , 2
Hence other zeroes are -1/2 and 2
☺ Hope this Helps ☺
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