Question

if 1 is a zero of the polynomial ax square - 3 bracket bracket 8 - 1 bracket x minus 1 then find the value of a

Answer 1

Here is your answer....

ax^2-3(a-1)x-1=0
Substitute 1 in the place of x
a-3 (a-1)-1=0
a-3a+1-1=0
-2a=0
a=0

Hope this will help your