Question

if 1 is a zero of the polynomial
ax2 - 3 (a-1) x-1 then find the value of a !

Answer 1

Answer:

The value of a is 1.

Step-by-step explanation:

Given that if 1 is a zero of the polynomial  

$ax^2-3(a-1)x-1$

we have to find the value of a

As 1 is one of the zero of above polynomial therefore by remainder theorem

P(1)=0

$a(1)^2-3(a-1)(1)-1=0$

$a-3(a-1)-1=0$

$a-3a+3-1=0$

$-2a+2=0$

$2a=2$  ⇒  $a=1$

The value of a is 1.

Answer 2

Answer: 1

Step-by-step explanation:

p(x) = ax²- 3(a-1)x -1

Given, 1 is its zero

p(x) = a(1)² -3(a-1)1 -1 = 0

a - 3a+3 -1 = 0

-2a + 2 = 0

-2a = -2

a = -2/-2

a = 1