if 1 is a zero of the polynomial ay^2+ay+3 and y^2+y+b, then find the value of a and b
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Let p(y) = ay² + ay + 3 and g(y) = y² + y + b
If 1 is the zero of p(y) and g(y) then,
p(y) = ay² + ay + 3
→ p(1) = a(1)² + a(1) + 3
→ 0 = a + a + 3
→ 0 = 2a + 3
→ 2a = -3
→ a = -3/2
g(y) = y² + y + b
→ g(1) = 1² + 1 + b
→ 0 = 1 + 1 + b
→ 0 = 2 + b
→ b = -2
Hence, a = -3/2 and b = -2
Good luck.
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