if -1 is a zero of the polynomial f(x)=x^-7x-8,then find the other zero
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p(x) = x²-7x-8
Zero = -1
x = -1
x+1 = 0
x+1 is a factor of x²-7x-8
we divide x²-7x-8 by x+1
=x²-7x-8/x+1
= x-8
x-8 = 0
x = 8
Therefore, the zeroes of x²-7x-8 are -1 and 8
Zero = -1
x = -1
x+1 = 0
x+1 is a factor of x²-7x-8
we divide x²-7x-8 by x+1
=x²-7x-8/x+1
= x-8
x-8 = 0
x = 8
Therefore, the zeroes of x²-7x-8 are -1 and 8
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