If 1 is a zero of the polynomial f(x) =x2k2-3xk+3k-1. Then the value of k is
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Answer:
Step-by-step explanation:
x = 2
=> (1)²k²-3(1)k+3k-1
=> k² - 3k + 3k - 1
=> k² = 1
=> k = 1
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