if 1 is a zero of the polynomial i(x)=ax²-3(a-1)x-1 then find the value of a
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Step-by-step explanation:
Hi,
X = 1
P(X) = ax²-3(a-1)x-1
P(1) = a * 1 - 3 ( a - 1) 1 - 1
=> a - 3a + 3 - 1
=> -2a + 2 = 0
=> -2a = -2
=> a = -2/-2 = 2/2 = 1
hence,
a = 1
Anonymous:
Osm
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