Math, asked by joelnoronha, 11 months ago

if 1 is a zero of the polynomial i(x)=ax²-3(a-1)x-1 then find the value of a

Answers

Answered by Panzer786
13

Step-by-step explanation:

Hi,

X = 1

P(X) = ax²-3(a-1)x-1

P(1) = a * 1 - 3 ( a - 1) 1 - 1

=> a - 3a + 3 - 1

=> -2a + 2 = 0

=> -2a = -2

=> a = -2/-2 = 2/2 = 1

hence,

a = 1


Anonymous: Osm
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