if 1 is a zero of the polynomial p x = 2 x square - 3 Y - 3 - 1 then find the value of a
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Answer:
p(x)= 2x^2 -3y -3 - 1
if 1 is th e zero of the polynomial, then
= 2(1)^2 - 3y -3 -1
= 2 -3y -3 -1
= -2 -3y
2= -3y
2/-3= y
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