Question

If 1 is a zero of the polynomial P (x)
= a x^2-3 (a -1) -1, Then the value of a
is​

Answer 1

Step-by-step explanation:

Given:-

1is a zero of the polynomial $\bf p(x)=ax^2-3(a-1)-1$

To find:-

Value of a

Solution:-

We know that

if

• 1 is a zero of the polynomial then p(1)=0

$\tt \longmapsto \: p(x) = ax {}^{2} - 3(a - 1) - 1 \\ \\ \tt \longmapsto \: p(1) = 0 \\ \\ \tt \longmapsto \: a {(1)}^{2} - 3(a - 1) - 1 = 0 \\ \\ \tt \longmapsto \: a - 3a + 3 - 1 = 0 \\ \\ \tt \longmapsto \: - 2a + 2 = 0 \\ \\ \tt \longmapsto \: - 2a = - 2 \\ \\ \tt \longmapsto \: a = \frac{ - 2}{ - 2} \\ \\ \tt \longmapsto \boxed{ \bf \: a = 1}$