Question

If 1 is a zero of the polynomial p(x)= ax^2-3 (a-1) x-1 then find the value of a?

Answer 1

Step-by-step explanation:

If 1 is a zero of the polynomial

$p(x) = a{x}^{2} - 3(a - 1)x - 1 \\ then \\ \: a( {1})^{2} - 3(a - 1)(1) - 1 = 0 \\ a - 3a + 3 - 1 = 0 \\ - 2a + 2 = 0 \\ 2a = 2 \\ a = 1$