Math, asked by dalbeer59, 2 months ago

if 1 is a zero of the polynomial p(x) = ax² - 3 ( a-1 ) x-1, find the value of 'a'

PLEASE tell me the answer​

Answers

Answered by sanskarkasrawad
0

Answer:

Solution. Now, we divide p ( x ) = a x 2 - 3 ( a - 1 ) x - 1 by x − 1. Hence, the value of a is 1 .

Step-by-step explanation:

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