Math, asked by maleeha5515, 10 months ago

If 1 is a zero of the polynomial p(x) = ax2 – 3 (a – 1) x – 1, then find the value of a

Answers

Answered by rahman786khalilu
2

Answer:

1 is zero of p(x)=ax^2-3(a-1)x-1

p(1)=a(1)-3(a-1)(1)-1=0

a-3(a-1)-1=0

a-3a+3-1=0

-2a+2=0

-2a=-2

a=-2/-2

a=1

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