If 1 is a zero of the polynomial p(x) = ax2 – 3 (a – 1) x – 1, then find the value of a
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1 is zero of p(x)=ax^2-3(a-1)x-1
p(1)=a(1)-3(a-1)(1)-1=0
a-3(a-1)-1=0
a-3a+3-1=0
-2a+2=0
-2a=-2
a=-2/-2
a=1
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