Question

If 1 is a zero of the polynomial p(x) = ax2 – 3(a – 1) x – 1, then find the value of a.

Answer 1

Answer:

a = 1

Step-by-step explanation:

p(x) = ax² - 3(a - 1)x - 1

= ax² - 3ax + 3x - 1

1 is zero of polynomial

put x = 1 in p(x)

p(1) = a(1)² - 3a(1) + 3(1) - 1

= a - 3a + 3 - 1

= -2a + 2 = 0

= 2a = 2

= a = 2/2

= a = 1

Answer 2

Answer:

p(1)= a*1*2-3(a-1)1-1

=2a-3a-3-1

=-a-4

.

. . 1=-a-4

1+4= -a

-5= a