If 1 is a zero of the polynomial p(x)= ax²-3(a-1)x-1 then find the value of a...
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Am not sure if the qs is right.if its wrong pls correct it n answer it ASAP
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Answered by
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Step-by-step explanation:
It is given that 1 is the zero of the polynomial p(x)
Therefore, p(1)=a(1)² -3(a-1)1 -1 = 0
a - 3a+3 -1 = 0
-2a + 2 = 0
-2a = -2
a = -2/-2
a = 1
Answered by
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Answer:
a=1 now look how
Step-by-step explanation:
ax^{2} -3(a-1)x-1
putting x=1
a-3(a-1)-1=0
2a=2
a=1
and also the question is right
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