Math, asked by sangeetasoni290845, 8 months ago

if 1 is a zero of the polynomial p (x) =ax2 - 3(a-1) x -1 then find the value of a​

Answers

Answered by dsohaib019
1

Answer:

P(1) = -(a + 1)

Step-by-step explanation:

x-1=0

x=1

P(1) =a(1)2 - 3(a-1)

P(1) = 2a - 3a -1

P(1) = -a-1

P(1) = -(a + 1)

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