Question

If 1 is a zero of the polynomial p(x)= ax² – 3(a-1)x-1 then find the value of a.​

Answer 1

Step-by-step explanation:

• put the value of x
• then u get a-3a+3-1=0
• so 2a=2
• therefore a=1

Answer 2

Given :

• p(x) = ax² - 3(a-1)x - 1
• 1 is zero of above polynomial

To find :

Value of a

Procedure :

• For a given , zero of polynomial (here 1) , value of p(x) { here p(1) } = 0
• Put p(x) = 0 , then solve for a

Solution :

p(1) = a(1²) - 3(a-1)×1 - 1

also , p(1) = 0

➠ 0 = a - 3(a-1) - 1

➠ 0 = a - 3a + 3 - 1

➠ 0 = 2 - 2a

➠ 2a = 2

➠ a = (2/2)

➠ a = 1

ANSWER :

a = 1