Question

If 1 is a zero of the polynomial P(x) =ax2+-3(a-1)x-1 then find the value of a.​

Answer 1

Answer:

a = 1

Step-by-step explanation:

P(x) = ax^2 + - 3(a - 1) × -1

P(0) = a(0)^2 + - 3(a - 1) × - 1

0 = - 3(a - 1) × - 1

0 = - 3a + 3 (- 1)

0 = 3a - 3

- 3a = - 3

a = - 3

-3

a = 3

3

a = 1

Hope it helps you....