Question

If 1 is a zero of the polynomial p(x) = ax² – 3(a – 1) x – 1, then find the value of a

Answer 1

Answer:

Now, we divide p ( x ) = a x 2 - 3 ( a - 1 ) x - 1 by x − 1. Hence, the value of a is 1

Step-by-step explanation:

Given: p(x)=ax

2

−3(a−1)x−1

One of the zero =1

As one of the zeroes is 1, substituting it in the polynomial

⇒p(1)=0=a−3(a−1)−1

⇒0=−2a+3−1

⇒a=1

Answer 2

Answer:

a=1

Step-by-step explanation:

p(1)=a(1)2 - 3×(a-1)×1 - 1=0

a-3a+3-1=0

-2a+2=0

-2a=-2

a=2/2=1