Question

If 1 is a zero of the polynomial p(x) = ax² – 3(a – 1) x – 1, then find the value of a.​

Answer 1

Answer:

a = 1

Step-by-step explanation:

Given: p(x) = ax² – 3(a – 1) x – 1,

One of the zero = 1

As one of the zeroes is 1, substituting it in the polynomial

⇒p(1)=0=a−3(a−1)−1

⇒0=−2a+3−1

⇒a=1

Answer 2

Step-by-step explanation:

because it's wrong

the zero of the polynomial is -2 by 3 II and II