Question

if 1 is a zero of the polynomial p(x) =ax2 -3(a-1)x-1, then find the value of a.
Give the with explaination..​

Answer 1

Answer:

Here,

p(x) =ax² -3(a-1)x - 1

and also given that 1 is a zero of this p(x)

So,

$\bold{ p(1) → a.1² - 3(a -1).1 -1 =0}$

$\bold{→ a - 3(a -1)-1 =0}$

$\bold{→ a - 3a + 3-1 =0}$

$\bold{→ - 2a + 2=0}$

$\bold{→2a = 2}$

$\bold{→ \large\boxed{\bold{a =1}}}$