Question

If 1 is a zero of the polynomial p(x)=ax2-3(a-1)x-1 then find the value of a

Answer 1

Answer:

Step-by-step explanation:

if 1 is a zero of p(x) then we should have

a - 3(a - 1) - 1 = 0, then

- 2a + 2 = 0

2a = 2

a =1

Answer 2

Answer:    

x-1 = 0

x = 1

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p(x)= ax^2 - 3a(a-x)x-1 = 0

p(1)=a-3a+3-1 =0

p(1)= -2a + 2 = 0

p(1) = 2a = 2

p(1) = a = 1

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