If -1 is a zero of the polynomial, p(x) = x2 – 2x -3, then the other zero is
(a) -3 (b) 3 (c) 0 (d) 1
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Answer:
p(-3)=-3×2-2×(-3)-3
=-6+6-3
=0-3
-3
p(3)=3×2-2×3-3
=6-6-3
=0-3
=-3
p(0)=0×2-2×0-3
=0-0-3
=-3
p(1)=1×2-2×1-3
p(1)=2-2-3
p(1)=0-3
-3
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