Question

if 1 is a zero of the polynomial p(x)=x²-3(a-1)x-1 then find the value of a.​

Answer 1

Step-by-step explanation:

have you got answer thanks

Answer 2

Answer:

$p(x) = x {}^{2} - 3(a - 1)x$

$g(x) = x - 1$

$p(x) = x {}^{2} - 3ax - 3x$

$p(1) = 1 {}^{2} - 3a(1) - 3(1)$

$0 = 1 - 3a - 3$

$0 = - 3a - 2$

$3a = - 2$

$a = \frac{ - 2}{3}$

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