If 1 is a zero of x3 – 3x2 – x + 3 then find all other zeroes.
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x³-3x²-x+3=0
x²(x-3)-1(x-3)=0
x-3(x²-1)=0
(x-3)(x+1)(x-1)=0
Zeros of the polynomial are 3,1,-1.
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Answer:
here you go...
Step-by-step explanation:
p(x)= x3-3x2-x+3
p(x) = (x-1)(x2-2x-3)
p(x) = (x-1)(x2-3x+x-3)
p(x) = (x-1)(x-3)(x+1)
Other two zeros are -1, 3.
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