Question

If 1 is a zero polynomial ax2 -3(a-1)x-1 then find a

Answer 1

ax2 kya likha h aapne square h kya

Answer 2

Given, a(x2 + 1) - x(a2 + 1)

= ax2 + a - xa2 - x

= ax2 - xa2 - x + a

= ax(x - a) - 1(x - a)

= (x - a)*(ax - 1)

To find roots, we have to equate (x - a) = 0 and (ax - 1) = 0

So, x - a = 0 and ax - 1 = 0

=> x = a, ax = 1

=> x = a, 1/a