If -1 is a zero polynomial p (x) = as cube - x square +x +4. Find the value of a
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Answered by
2
Answer:
heya mate there's your answer
as -1 is the zero of given polynomial it satisfies the p(x)
so apply it in p(x)
p(x)=ax^3-x^2+x+4=0
p(-1)=a(-1)^3-(-1)^2+(-1)+4=0
-a-(+1)-1+4=0
-a-1-1+4=0
-a-2+4=0
-a+2=0
-a=-2
a=2
hope it helps you
Thank you
riyadora01:
Thanx a lot yaar!!
Answered by
3
Answer:
4
Step-by-step explanation:
p(x) = ax³ - x² + x + 4
Given zero: -1
P(-1) = a(-1)³ - (-1)² + (-1) + 4
= a(-1) + (1) - 1 + 4
= -a + 1 - 1 + 4
= 4 - a
Since -1 is a zero of p(x), p(-1) = 0.
Thus, 4-a 0
Hence, a = 4.
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