Question

if 1 is a zerobof the polynomial p(x)=ax²-3(a-1)x-1then find the value of a

Answer 1

Hola there,

Given=>

p(x) = ax² - 3(a - 1)x - 1

p(1) = 0

So,

=> a(1)² - 3(a - 1)1 - 1 = 0

=> a - 3a + 3 - 1 = 0

=> -2a + 2 = 0

=> 2a = 2

=> a = 1. ...Ans

Hope this helps....:)

Answer 2

Hey! Here's your answer..
p(x)=ax^2-3(a-1)x-1
We are given that 1 is zero of p(x)
Then, p(1)=0
So,
a(1)^2-3(a-1)1-1=0
a-3a+3-1=0
-2a+2=0
-2a=-2
2a=2
a=1
Hence, the value of a = 1
Hope it helps!!