Question

If 1 is added to the numerator of a certain fraction it's value becomes 1/2 and if 1 is added
to its denometer 1/3 . Find the original fraction.​

Answer 1

Answer:

let the original fraction be x/y

A/c to question

x+1/y=1/2

2x-y+1=0. _(1)

and

x/y+1=1/3

3x-y-1=0. _(2)

equation (1) - (2)

we get

x=2

by this value of x we can get the value of y i.e., y=5

so the required fraction is 2/5