Question

if 1 is added to the numerator of a certain fraction its value becomes 1 upon 2 and if 1 is added to its denominator its value becomes 1 upon 3 find the original fraction ​

Answer 1

$let \: the \: fraction \: be \: \frac{ x}{y} . \\ according \: to \:question \\ \frac{x + 1}{y} = \frac{1}{2} ..........eq(i) \\ and \: \\ \frac{x}{y + 1} = \frac{1}{3}..........eq(ii) \\ from \: eq(i) \\ 2x + 2 = y \\ 2x - y = - 2.........(1) \\ from \: eq(ii) \\ 3x = y + 1 \\ x = \frac{y + 1}{3} \\ putting \: this \: value \: of \: x \: in \: (1) \\ 2( \frac{y + 1}{3} ) - y = - 2 \\ 2y + 2 - 3y = - 6 \\ - y = - 6 - 2 \\ y = 8 \\ x = \frac{y + 1}{3} = \frac{8 + 1}{3} \\ x = 3 \\ the \: fraction \: is \: \frac{3}{8}$

if it helps you mark as brainliest.

Answer 2

hope it helps !!

mate!! ur answer is in image