if 1 is added to the numerator of a fraction a/b becomes 5/6 if 2 is subtracted from denominator it becomes 9/10
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There is a mistake in the given attachment,
Solution,
When 1 added to numerator,
Fraction = (a+1)/b
(a+1)/b = 5/6
From this,we conclude that a = (5b- 6)/6
============
When 2 is subtracted from denominator,
Fraction = a/(b -2)
a/(b-2) = 9/10
10a = 9b - 18
Putting the value of a from the above solution,
10[(5b-6)/6] = 9b - 18
25b - 30 = 27b - 54
-30 + 54 = 27b - 25b
24 = 2b
12 = b
=========
a = [(5b-6)/6)]
a = [(60-6)/6]
a = 54/6
a = 9
Now,
Fraction = 9/12
I hope this will help you
-by ABHAY
Solution,
When 1 added to numerator,
Fraction = (a+1)/b
(a+1)/b = 5/6
From this,we conclude that a = (5b- 6)/6
============
When 2 is subtracted from denominator,
Fraction = a/(b -2)
a/(b-2) = 9/10
10a = 9b - 18
Putting the value of a from the above solution,
10[(5b-6)/6] = 9b - 18
25b - 30 = 27b - 54
-30 + 54 = 27b - 25b
24 = 2b
12 = b
=========
a = [(5b-6)/6)]
a = [(60-6)/6]
a = 54/6
a = 9
Now,
Fraction = 9/12
I hope this will help you
-by ABHAY
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