Question

if 1 is added to the numertor of certain fraction value becames 1/2 and if 1 is added to denominator 1/3 find orignal value​

Answer 1

Let the numerator be x and denominator be y

x+1/y=1/2

Cross multiplying

2(x+1)=y

2x+2=y

2x-y=-2

also,

x/y+1=1/3

3x=y+1

3x-y=1

Using elimination method,

2x-y=-2

3x-y=. 1

- + -

----------------------

-x. =-3

x. = 3

Putting value of x in 2x-y=-2

2×3-y=-2

6-y=-2

-y=-2-6

-y=-8

y=8

So the fraction is 3/8

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